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18a^2-15a=3a
We move all terms to the left:
18a^2-15a-(3a)=0
We add all the numbers together, and all the variables
18a^2-18a=0
a = 18; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·18·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*18}=\frac{0}{36} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*18}=\frac{36}{36} =1 $
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